Algebra 1 Rate Of Change

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ALGEBRA 1 LESSON half dozen -1 Charge per unit of Change and Slope (For help, go to Lessons v -ii and 1 -v. ) Evaluate each office rule for x = – five. i. y = x – 7 2. y = 7 – 10 3. y = 2 x + five 2 4. y = – x + 3 5 Write in simplest form. 5. 7– 3 3– 1 viii. – 1 – 2 0– 5 six. 3– five half dozen– 0 ix. – 6 – (– 4) – 2 – vi 8 -3 7. viii – (– 4) three– vii 10. 0 – 1 1– 0

ALGEBRA one LESSON 6 -1 Rate of Change and Slope For the data in the tabular array, is the charge per unit of alter the aforementioned for each pair of consecutive mileage amounts? Fee for Miles Driven Miles 100 Fee $30 150 $42 200 $54 250 $66 Find the rate of change for each pair of sequent mileage amounts. eight -iii

ALGEBRA ane LESSON 6 -1 Rate of Modify and Slope (continued) rate of change = change in price change in number of miles 42 – 30 12 = 150– 100 l 54 – 42 12 = 200– 150 50 Toll depends on the number of miles. 66 – 54 12 = 200– 250 50 The rate of change for each pair of consecutive mileage amounts is $12 per 50 miles. The rate of change is the aforementioned for all the information. eight -3

ALGEBRA one LESSON 6 -1 Rate of Change and Slope Below is a graph of the altitude traveled past a motorcycle from its starting betoken. Find the rate of change. Explain what this charge per unit of change ways. Choose two points On the graph (0, 0) and (400, twenty) 8 -3

ALGEBRA 1 LESSON 6 -i Rate of Change and Slope (continued) Using the points (0, 0) and (400, xx), find the rate of change = = vertical change horizontal change 400 – 0 change in distance change in time Use two points. 20 – 0 Separate the vertical alter by the horizontal change. 400 20 Simplify. xx The rate of change is twenty m/south. The motorcycle is traveling 20 meters each second. 8 -3

ALGEBRA 1 LESSON 6 -i Rate of Change and Slope Find the slope of each line. a. gradient = rise run = 4– one 0– 2 = 3 – 2 =– 3 2 The gradient of the line is – iii. 2 viii -three

ALGEBRA 1 LESSON half dozen -one Charge per unit of Alter and Gradient (connected) b. Find the slope of the line. slope = = ascension run – i – 2 – (– two) = – 2 – i = 2 The slope of the line is 2. 8 -3

ALGEBRA 1 LESSON half-dozen -ane Rate of Change and Slope Detect the slope of each line through E(three, – 2) and F(– two, – 1). y 2 – y 1 slope = x ii – ten 1 = – 1 – (– ii) Substitute (– two, – i) for (ten two, y ii) and (3, – 2) for (x i, y 1). – two – three = – 51 Simplify. = – xv The gradient of EF is – one. five 8 -3

ALGEBRA 1 LESSON half dozen -1 Charge per unit of Modify and Gradient Notice the slope of each line. a. slope = = y 2 – y 1 10 2 – 10 ane ii– 2 1 – (– iv) = 0 v Substitute (1, 2) for (x 2, y 2) and (– four, 2) for (x 1, y 1). Simplify. = 0 The slope of the horizontal line is 0. 8 -3

ALGEBRA 1 LESSON 6 -one Rate of Modify and Slope (continued) b. Find the slope of the line. y –y slope = x 2 – x 1 2 1 = 1 – (– iv) Substitute (2, one) for (10 2, y ii) and (2, – 4) for (x 1, y 1). = v Simplify. two– two 0 Division by zero is undefined. The gradient of the vertical line in undefined. 8 -3

ALGEBRA one LESSON 6 -1 Charge per unit of Change and Slope i. Observe the rate of change 2. Find the rate of change 3. Find the slope of the line. for the information in the table. for the information in the graph. Tickets Cost 5 6 seven viii $75 $ninety $105 $120 iv. Find the gradient of the line through (iii, – 2) and (– ii, v). 8 -3

ALGEBRA 1 LESSON 6 -1 Charge per unit of Change and Slope v. State whether the slope is nil or undefined. a. b. eight -3

ALGEBRA 1 LESSON six -one Rate of Change and Slope i. Find the rate of change two. Detect the rate of change 3. Detect the slope of the line. for the data in the table. for the information in the graph. Tickets Toll 5 half dozen 7 8 $75 $90 $105 $120 $xv per ticket 4 iii 400 calories per hour four. Find the slope of the line through (3, – ii) and (– 2, 5). – 8 -three 7 5

ALGEBRA 1 LESSON 6 -i Rate of Change and Slope 5. State whether the slope is zippo or undefined. a. b. undefined 0 8 -iii

Algebra 1 Rate Of Change,

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